Below are few sample aptitude questions of the difficulty level that can be expected on Tech Mahindra's placement tests/ interviews.
Placement Question 1
Consider a group of working men. If 1/10th of the workers are absent then work of each person would be increased by.
a. 20% b. 22.22% c. 10% d. 11.11%
Answer is d. 11.11%
Let us assume 100 units of work is divided among 10 men.
When no one is absent, each member have to do 100/10 = 10 units of the work
With 1/10th of men absent, there would be 9 men present.
Now, if 100 units of work is to be done by the 9 men present, each should do 100/9 units of work.
Extra work required from each member when only 9 men are present = 100/9 - 10 = 10/9 units.
Percentage of increase of work for each member = (Extra work required from each member when only 9 men are present)/ (Original amount of work when everyone is present) X 100 % = ((10/9)/10)X 100% = 11.11%
Placement Question 2
Consider the following statements,
All members of team A are good tall guys with an average height of 6 feet.
Average of the height of members of team B is lesser than that of team A.
Which could be true among the below options.
a) Every member of team B is shorter than each member of team A.
b) Few members of team B could be over 6 feet.
Answer is Option b) Few members of team B could be over 6 feet.
Reason : The statement says that there is a possibility that few members of team B can actually be taller than few members of team A.
Placement Question 3
John is supposed to walk from his house to park every morning. One morning, he is in real hurry and wants to save at least 1/3rd of the time. By how much percentage he should increase his speed.
a. 100% b. 33% c. 66% d. 50%
Answer is d. 50%
Let the distance between his house and park be 100 metres.
Lets assume he takes 30 mins daily. Hence his speed would be 100/30.
One day, if he wishes to save 1/3rd of 30 minutes, that is 10 minutes, he should cover the distance in 20 minutes in which case his speed would be 100/20.
Required increment in speed = 100/20 - 100/30
Percentage of increase in speed = (Required increment in speed / Original speed) X 100 % = ((100/20 - 100/30) / 100/30 )X100 % = 50%.