Placement Question 1 :

Below are few Infosys type sample verbal questions. These questions require you to fill in the given sentence with
appropriate word from the given options. These types of questions can also be expected in placement papers of several other companies like CTS, TCS, Wipro etc. In fact, any company which has verbal section, generally has at least five to ten questions of the below type.

1) A man has Ten Horses and nine stables as shown here.
[ ] [ ] [ ] [ ] [ ] [ ] [ ] [ ] [ ]
The man wants to fit Ten Horses into nine stables. How can he fit Ten horses
into nine stables?

Answer
The answer is simple. It says the man wants to fit "Ten Horses" into nine stables.

Solved general aptitude questions from Infosys Placement Papers

Part 1 of solved aptitude questions from Infosys Placement Papers

Part 2 of solved aptitude questions from Infosys Placement Papers

Here are some solved questions from  Infosys  Placement Papers

1) Eight friends Harsha, Fakis, Balaji, Eswar, Dhinesh, Chandra, Geetha, and Ahmed are sitting in a circle facing the center. Balaji is sitting between Geetha and Dhinesh. Harsha is third to the left of Balaji and second to the right of Ahmed. Chandra is sitting between Ahmed and Geetha and Balaji and Eshwar are not sitting opposite to each other. Who is third to the left of Dhinesh?

Answer:
                            Ahmed
 
                   Fakis              Chandra
             Harsha                      Geetha  

                   Eswar            Balaji
                               Dhinesh    

2) A fast typist can type some matter in 2 hours and a slow typist can type the same in 3 hours. If both type combinely, in how much time will they finish?

Answer : 1 hr 12 min
Explanation : The fast typist's work done in 1 hr = 1/2
The slow typist's work done in 1 hr = 1/3
If they work combinely, work done in 1 hr = 1/2+1/3 = 5/6
So, the work will be completed in 6/5 hours. i.e., 1+1/5 hours = 1hr 12 min

3) 3)1, ? , 9, 7, 7, 9, 13, 10, 9, 1, 4, 9, 16, 16, .....
What number comes at '?'  at the second place from the start ?

Answer:
THE SERIES IS THE SUM OF THE DIGITS IN THE SQUARE OF NATURAL NUMBERS :
1^2 - 1 - 1
2^2 - 4 - 4
3^2 - 9 - 9
4^2 - 16 - 1+6 - 7
5^2 - 25 - 2+5 - 7
............
Answer is 4.

4) Today is 4.11.09. keeping that figure 41109 in mind, i have arrived at the following

sequence : 2, 1, 9, 5, ? which of the following four numbers suits '?'

a) 7
b) 65
c) 4563
d) 262145

Answer is:
41109
1^4 + 1 = 2
1^1 + 0 = 1
0^1 + 9 = 9
9^0 + 4 = 5
So next is 4^9 + 1 = 262145

Here are some solved questions from Infosys Placement Papers

1) In a race Andrew beats Jim. Jack is not the last. Dennis loses to both Jack and Lucia.
Jim beats Jack. Who won the race?

ANSWER:

  The possible positions in the race are,
 Andrew       Andrew
 Jim              Jim
 Jack            Lucia
 Lucia          Jack
 Dennis       Dennis
In either case Andrew is the winner.

2) Find the digits X,Y,Z
X X X X
Y Y Y Y  +
Z Z Z Z
-----------------
    Y X X X Z
-----------------

ANSWER:
x+y+z = z ==> x+y = 10
max value for y = 1
hence x = 1
also, (carry)1+x+y+z = x ==> 1+y+z = 10
          hence z=8
         X   Y   Z
         9   1   8

3) A 1 k.m. long wire is held by n poles. If one pole is removed, the length of the gap
becomes 12/3m. What is the number of poles initially?

ANSWER:
Let the no. of poles originally = n
After taking away one pole
 (n-1)*12/3 = 1000
 n = 251

4) A + B + C +D = D + E + F + G = G + H + I =17.

IF A = 4 WHAT ARE THE VALUES OF D AND G. EACH LETTER
TAKEN ONLY ONE OF THE DIGIT FROM 1 TO 9.      

         
Answer:
 A = 4 ,B = 2, C =6, D = 5, E = 3, F = 8, G = 1,H = 7, I = 9.

Here are some solved questions from Infosys Placement Papers

1) The L.C.M. (Lowest (or Least) Common Multiple) of two numbers is 45 times to their H.C.F (Highest Common Factor). If one of the numbers is 125 and sum of L.C.M. and H.C.F. is 1150, the other number is:

a) 215
b) 220
c) 225
d) 235

Solution: Let L.C.M. be l and H.C.F. be h. Then l = 45h
l + h =1150
This gives h =25 and l = 1125
Thus the second number = (25 * 1125)/125 = 225

2) Six bells commence tolling together and toll at intervals 2,4,6,8,10 and 12 seconds respectively. In 30 minutes how many times they toll together.

a) 4
b) 10
c) 15
d) 16

Solution: L.C.M. of 2,4,6,8,10,12 = 120
So they toll together after every 120 seconds i.e. 2 minutes. So in 30 minutes they toll together 30/2 + 1 = 16 time

3) The value of (0.625 * 0.0729 * 28.9)/(0.0017 * 0.025 * 8.1) is

a) 0.3825
b) 3.825
c) 38.25
d) 382.5

Solution: The sum of decimal places in numerator and denominator being the same, decimal point can be removed
(625*729*289) / (17*25*81) = 3825

4) Linear equations are part of all math aptitude tests. They can be age related problems, upstream, downstream problems etc
I am three times as old as my son. Five years later I shall be two and a half times as old as my son. What is my age?

Solution:
Let my age be x years and age of my son be y years.
(i) x = 3y
Five years later
(ii) x+5 = 5/2(y+5)
From (i) and (ii)
y=15 and x=45

1) Can you find out what day of the week was January 12, 1979?

Ans. Friday.

2) Find x+2y

(i). x+y=10
(ii). 2x+4y=20

Ans: (b)