Here are some solved questions from Accenture Placement Papers

1)  Using two 2's and two 3's and using a maxm of three mathematical signs, symbols, can you have a result in between 14 and 15 ? concatanation ( clubbing of digits ) allowed.

Solution:
( 23 + 3! ) / 2 = 14.5

2) what is the 28383rd term in the series 1234567891011121314............
 
a) 3
b) 4
c) 7
d) 9

Solution:
there are 9 no. of single digit
there are 180 no. of double digit
there are 2700 no. of three digit
now total 2889 no. till 999
remaining no. are 25494 that is devided by 4 and the q is 6373 with reminder of 2 so 28381 is
6373+999=737(2)
n next no is 7(3)73
so ans is 3

3)  a*b*c*d*e + b*c*d*e*f + a*c*d*e*f + a*b*d*e*f + a*b*c*e*f + a*b*c*d*f = a*b*c*d*e*f  and a,b,c,d,e and f are all positive nonrepeating integers then solve a,b,c,d,e, and f.

Solution :
Start with 1/2 + 1/2, then progressively split the last part x
into 2x/3 + x/3.  This gives the following progression:
2,2
2,3,6
2,3,9,18
2,3,9,27,54
2,3,9,27,81,162

4) 729 ml of a mixture contains milk and water in ratio 7:2. How much of the water is to be added to get a new mixture containing half milk and half water?

(i) 79 ml
(ii) 81 ml
(iii) 72 ml
(iv) 91 ml

Solution:
Milk = (729 * (7/9))=567ml
Water = (729-567)= 162ml
Let water to be added be x ml 567/(162+x) = 7/3 1701 = 1134 + 7x x = 81ml