Dear Reader, below are three puzzle questions that can help you to practice for Infosys placement tests.

Question 1

Aravamudhan gives Babu as many rupees as Babu has and Chiranjeevi as many rupees as Chiranjeevi has. Similarly, Babu then gives Aravamudhan and Chiranjeevi as many rupees as each of them has. Chiranjeevi, similarly gives Aravamudhan and Babu as many rupees as each of them has. Now finally each of them has Rs.32, with how many rupees does Aravamudhan start?

a)52 b)56 c)60 d)62

Answer : a)52

Solution :

We have to take a bottom up (reverse) approach to tackle these kinds of problems. Below are the steps to solve this problem.

				Aravamudhan		Babu	Chiranjeevi
Finally					32		32		32
Before Chiranjeevi gives		16		16		64 
Before Babu gives			 8		56              32	
Before Aravamudhan gives		52		28		16 

Hence, Aravamudhan start with Rs 52.

Question 2

Fifty one books are arranged from left to right in order of increasing prices. The price of each book differs by Rs. 2 from that of each adjacent book. For the price of the book at the extreme right a buyer can buy the middle book and an adjacent one. Then, which of the following statements is correct ?

a) The adjacent book referred to is at the left of the middle magazine.
b) The middle book sells for Rs. 56
c) The most expensive book sells for Rs.116
d) None of the above statements is correct.

Answer : a) The adjacent book referred to is at the left of the middle magazine.

Solution :

Let the price of the first book be B
Price of the last book (51st) will be B + (2 x 50)
= B + 100
Price of the middle book = B + (2 x 25) = B + 50
Price of the book to the left of middle book = Price of the middle book – 2 = B + 48
But, from the question, we can infer that,
Price of the middle book + Price of the book to the left of middle book = Price of the last book.
B + 50 + B + 48 = B + 100
B = 2
Instead if the buyer buys the middle book and the book adjacent right side
B + 50 + B + 52 = B + 100
B = -2 (not possible)
Cost of middle book = 2 + 50 = 52
Price of the Most expensive book (i.e last book) = B + 100 = 2 + 100 = Rs.102.
Hence a) is correct.

Question 3

A group of six friends are sitting around a hexagonal table, each one at one corner of the hexagon. (facing the centre inside) Raman is sitting opposite to Ramesh. Jolly is sitting next to Seema. Neeta is sitting opposite to Seema, but not next to Ram. Amit has a person sitting between Ramesh and himself. If Neeta sits to the right of amit, then who is sitting to the left of Amit?

a)Ramesh b)Raman c)Jolly d) Seema

Answer : b) Raman

Solution :

Based on the information provided, seating pattern will be drawn as above
Clockwise = AMIT – RAMAN - SEEMA - JOLLY- RAMESH - NEETA