Dear Reader, Below are three aptitude questions requiring you to apply your logical skills to the extent possible. Though there could be several ways to solve these kinds of questions, drawing diagrams to crack these can help a lot.
Anand is the brother of Bachan. Coolie is the son of Bachan. Divya, the daughter of anand, is married to Elgin. Fox and Bachan are sisters.
Now consider the below proposed conclusions:
Conclusion 1) Divya is the daughter of Fox.
Conclusion 2) Coolie is brother of Divya.
Conclusion 3) Elgin is son-in-law of Anand.
Conclusion 4) Fox is sister of Coolie.
Which of the following statements is true.
a) Conclusions 1) and 2) are true
b) Conclusions 1) and 3) are true
c) None of the above.
d) Conclusion 3) alone is true
Answer : d) Conclusion 3) alone is true:
Based on the information given in the question, one can draw a diagrammatic representation as given below.
(In the above diagram, a forward arrow from a person A to person B indicates that A is related to B as given in the label near that particular arrow.)
Comparing this with the conclusions 1,2,3 and 4, One can easily say that only conclusion 3 is true. Therefore option d is true.
Anand’s daughter Divya and her husband is Elgin. Hence Elgin is son-in-law of Anand.
P,Q,R,S,T, U, V and W are eight classmates studying in Padma Seshadri School, KK Nagar, Chennai. They are standing along the four sides of a square, two on each side. P is oppoisite V, R is opposite T, S is on the same side as V, W is opposite Q and T is on the side as Q.
If the above information is true, which of the following is true?
a) T is on the side of P.
b) U is on the side of P.
c) R is on the side of Q.
d) P is on the side of S.
Answer : b) U is on the side of P.
The information provided may be drawn in
Clockwise – TQ,VS,RW,PU
Comparing the above diagram with the options given, one can easily say that option b is the correct one.
Hence choice b) is correct.
Six paintings – F, G, H, J, K and L – are to be sold at a three day auction.
The paintings are to be divided into three groups – group 1, group 2 and group 3 – and each group is to be sold on one of the days of the auction. The paintings to be included in each group are to be selected according to the following conditions.
1.Group 2 must contain at least as many paintings as Group 1 and Group 3 must contain at least as many paintings as Group 2.
2.H and K, paintings by the same artist, must be in the same group as each other.
3.F and L paintings of similar subjects, must be in different groups from each other.
4. G and H estimated to be the two most valuable paintings, must be in different groups from each other.
5. If J is in group 3, K must also be in group 3 because of a request from the auctioneer for the third day.
If H is in group 1, which of the following must be true?
a) F is in group 2.
b) G is in group 2.
c) J is in group 2
d) L is in group 2
Answer : c) J is in group 2.
Rule 1 states that Group 2 must contain at least as many paintings as Group 1 and Group 3 must contain at least as many paintings as Group 2 i.e. G1 ≤ G2 ≤ G3 where G1, G2, and G3 are the number of paintings of Group 1, Group 2 and Group 3 respectively. As the total number of paintings is 6, they can be divided into three groups in three possible ways
In the question it is given that H is in group 1.
From rule 2, K should be in the same group as H.
Hence H and K are in G1. (There can be no more paintings in group 1 as the diagram above clearly indicates that there is no way for group 1 or group 2 to have more than 2 paintings.)
Rule 5 states that if J has to be in group 3, K also has to be in group 3. But as per last paragraph, we know that K is in group 1 and not in group 3. Hence J cannot be in group 3. Therefore it needs to be in group 2.
Since J has to be in group 2, option C is certainly true without doubt.